How can I trim data from a value inside array?

Question

This is my data:

$d = $request->request->get('data');

The output:

[{"name":"form[id]","value":"10"},{"name":"form[name]","value":"Telefon2"},{"name":"form[uuid]","value":"bb80878ad4"},{"name":"form[productgroup]","value":"6"},{"name":"form[category]","value":"1"},{"name":"form[documents]","value":"7"}

I want to create a new array, that is removing extracting the variable inside the brackets.

 function trim($d) {
          preg_match('#\[(.*?)\]#', $d, $match);
          return $match[1];
   }


$dData = array_combine(array_column(trim($d), 'name'), array_column($d, 'value'));
$json = json_encode($dData);

But the error is

Warning: preg_match() expects parameter 2 to be string, array given

Isn't your output missing a ] ? If it is then your output must be a json — Andrei Lupuleasa
– Andrei Lupuleasa, Commented Mar 21, 2019 at 8:16
Why do you try regex at all? What is the expected $json result? — Pinke Helga
– Pinke Helga, Commented Mar 21, 2019 at 8:22
I neither understand why do you use preg_match. Did you consider using array_map? — guyaloni
– guyaloni, Commented Mar 21, 2019 at 8:25

BritishWerewolf · Accepted Answer · 2019-03-21 10:09:41Z

2

You're going to need to do a few things before you begin.

Firstly, rename the trim function to something like extract_name because PHP already has a built in trim function that removes whitespace from a string - or any character present in the character mask.
Secondly, you are going to need to iterate over each of the elements in the name column. You will notice the error you are getting from preg_match is because you are passing all values in one go.
Thirdly, I am assuming that the value of $d is an array of PHP objects. This is done, and assumed, in my solution using $d = json_decode($d);.

Using array_map instead of a foreach means we can have a nice one liner:

function extract_name($d) {
    preg_match('#\[(.*?)\]#', $d, $match);
    return $match[1];
}

$dData = array_combine(array_map('extract_name', array_column($d, 'name')), array_column($d, 'value'));

The output being:

array:6 [
  "id" => "10"
  "name" => "Telefon2"
  "uuid" => "bb80878ad4"
  "productgroup" => "6"
  "category" => "1"
  "documents" => "7"
]

Live demo

edited Mar 21, 2019 at 10:09

BritishWerewolf

3,9785 gold badges34 silver badges54 bronze badges

answered Mar 21, 2019 at 8:26

ErrorException

365 bronze badges

Sign up to request clarification or add additional context in comments.

5 Comments

peace_love Over a year ago

Thank you, this sounds like a good solution. I tested it but I get the error message Warning: array_map() expects parameter 1 to be a valid callback, function 'new_trim' not found or invalid function name

ErrorException Over a year ago

@monkeylove I have updated the question. As I said in the answer, you need to rename your original function to be called extract_name and then it will work.

peace_love Over a year ago

Yes, this is what is confusing me.. However I name it, the error message is:

Warning: array_map() expects parameter 1 to be a valid callback, function 'extract_name' not found or invalid function name

BritishWerewolf Over a year ago

@monkeylove Are you sure you are copying this answer correctly? I have added a live demo to this answer to make it clearer what I think the poster was trying to accomplish.

ErrorException Over a year ago

@monkeylove Is the function declared in the same scope as $dData? Have you copied my snippet? The function must have the same name as a the string that you are passing to array_map. If that doesn't work, try creating an anonymous function instead and seeing if you are still having problems.

Vasil Kulakov · Accepted Answer · 2019-03-21 08:26:51Z

-1

I believe you need smth like this


$d = ['{"name":"form[id]","value":"10"}', '{"name":"form[name]","value":"Telefon2"}', '{"name":"form[uuid]","value":"bb80878ad4"}', '{"name":"form[productgroup]","value":"6"}'];

function combine(array $d): array
{
    $res = [];
    foreach ($d as $item) {
        $value = json_decode($item, true);
        preg_match('#\[(.*?)\]#', $value['name'], $match);;
        $columnName = $match[1];
        $res[$columnName] = $value['value'];
    }

    return $res;
}


$dData = combine($d);
$json = json_encode($dData);
echo $json;```

answered Mar 21, 2019 at 8:26

Vasil Kulakov

3103 silver badges4 bronze badges

Collectives™ on Stack Overflow

How can I trim data from a value inside array?

2 Answers 2

5 Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

5 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related