Coding Help (If Statements)

Question

Let's say I have a sample code, something like this

public double {method} ()
{
if (stringThatCalledThisMethod.equalsIgnoreCase("x")) // x = A String
{
return 100 ;
}
else if (stringThat....equalsIgnoreCase("y"))         // y = A String
{
return 999 ;
}

How would I call for the string that called that method? (In this instance any string can call for the method and it will always be different)

(Using this does not work as I get an error saying "Cannot find Symbol | symbol: method equalsIgnoreCase(String)

I am trying to convert a string to a double (Not sure if there is an easier way)

pass stringThatCalledThisMethod as method param double {method} (String stringThatCalledThisMethod) — karan
– karan, Commented Mar 25, 2019 at 4:50
You want to know the name of the method that called another method from inside the called method? — Bohemian
– Bohemian ♦, Commented Mar 25, 2019 at 4:52

PumpkinX · Accepted Answer · 2019-03-25 04:57:53Z

1

To convert a string to double, following code should do:

public double doubleString(String text){

        return Double.parseDouble(text);

}

You might want to catch NumberFormatException to handle the case of invalid value to cast as Double.

answered Mar 25, 2019 at 4:57

PumpkinX

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Comments

Jaspreet Jolly · Accepted Answer · 2019-03-25 07:31:28Z

0

I am guessing that you need name of the caller method and then compare it. As per my understanding this is what you need.

String callerMethodName = Thread.currentThread().getStackTrace()[2].getMethodName();

Note that you might need to replace the 2 with 1.

Other way could be sending method name as param in your 2nd method like:-

public double method2(String callerMethodName){

}

answered Mar 25, 2019 at 7:31

Jaspreet Jolly

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