PHP DateTime accepting invalid date

Question

I'm having trouble using the PHP DateTime class, and more specifically the DateTime::createFromFormat().

I get a date from a string, then try to instanciate a DateTime object, using DateTime::createFromFormat(). But, when I give this function a date that cannot exist, it is still working, returning me a valid DateTime object, with a valid date, which isn't the date I gave it.

Code example :

$badDate = '2010-13-03';
$date = DateTime::createFromFormat('Y-m-d', $badDate);

var_dump($date);

/*
object(DateTime)#284 (3) {
["date"]=>
string(19) "2011-01-03 10:01:20"
["timezone_type"]=>
int(3)
["timezone"]=>
string(13) "Europe/Berlin"
}
*/

Any ideas? I really need a way to check date validity.

Thank you.

Edit:

I just found why, see my answer.

Clement Herreman · Accepted Answer · 2011-04-04 08:28:58Z

16

DateTime::createFromFormat doesn't throw exception/return false when the given date is impossible. It try to guess the expected date.

If you give it '2010-01-32' (as in Januar, 32th), it will return a DateTime object containing Februar, 1st (Januar 31th + 1 day). Must be logical... in some weird twisted way.

To check the validity, you must check the DateTime::getLastErrors() which contains warning, like for my case :

array(4) {
  ["warning_count"]=>
  int(1)
  ["warnings"]=>
  array(1) {
    [10]=>
    string(27) "The parsed date was invalid"
  }
  ["error_count"]=>
  int(0)
  ["errors"]=>
  array(0) {
  }
}

This behavior seems to come from the UNIX timestamp which PHP calculate, based on the year, month and date you give it (even if the date is invalid).

answered Apr 4, 2011 at 8:28

Clement Herreman

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2 Comments

Jan K. S. Over a year ago

"Must be logical... in some weird twisted way." ==> Oh, we see that a lot in PHP.

Optimae Over a year ago

Anyone reading this remember to check for both warnings AND errors, especially if you write your own isValidDate function to wrap around this.

Glavić · Accepted Answer · 2013-09-29 18:49:09Z

16

I found example where validation based on DateTime::getLastErrors() will fail, so better solution would be to compare inputed date with generated date.

Code:

function validateDate($date, $format = 'Y-m-d')
{
    $dt = DateTime::createFromFormat($format, $date);
    return $dt && $dt->format($format) == $date;
}

Use example:

var_dump(validateDate('2012-02-28')); # true
var_dump(validateDate('2012-02-30')); # false

# you can validate and date/time format
var_dump(validateDate('14:50', 'H:i')); # true
var_dump(validateDate('14:99', 'H:i')); # false

# this is the example where validation with `DateTime::getLastErrors()` will fail
var_dump(validateDate('Tue, 28 Feb 2012 12:12:12 +0200', DateTime::RSS)); # true
var_dump(validateDate('Tue, 27 Feb 2012 12:12:12 +0200', DateTime::RSS)); # false

answered Sep 29, 2013 at 18:49

Glavić

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4 Comments

Clement Herreman Over a year ago

ouch, nice catch. What version of PHP are you using for this test? Maybe this was fixed along the way?

Glavić Over a year ago

@ClementHerreman: this result is on all PHP version that support DateTime::createFromFormat, that is all above php >= 5.3.0. See it in action here. I never said that DateTime::getLastErrors() should report warning or error in this case, probably this works as intended (ignoring string days), but IMO, if we are doing validation function, it should matter, because 27 Feb 2012 is not Tuesday, it is Monday.

Glavić Over a year ago

In this example DateTime::getLastErrors() reports error only in case if textual day cannot be found or it is invalid, see.

Chris Over a year ago

Much nicer solution, as this should handle both errors and warnings. Thanks!

krookedking · Accepted Answer · 2011-04-04 15:23:22Z

15

You have to make use of DateTime::getLastErrors() which will contain the error The parsed date was invalid.

$badDate = '2010-13-03';
$date = DateTime::createFromFormat('Y-m-d', $badDate);
if( DateTime::getLastErrors()['warning_count'] > 0 ){
 //not a correct date
}else{
 //correct date
 print $date->format('Y-m-d');
}

edited Apr 4, 2011 at 15:23

answered Apr 4, 2011 at 8:23

krookedking

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Comments

Xavi Montero · Accepted Answer · 2019-03-21 04:13:16Z

4

Look for checkdate() function at php documentation. It will help you :)

edited Mar 21, 2019 at 4:13

Xavi Montero

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answered Apr 4, 2011 at 8:20

ayk

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1 Comment

Xavi Montero Over a year ago

This should have been the answer.

jeremyFreeAgent · Accepted Answer · 2011-04-04 08:21:12Z

1

You can do that :

DateTime::getLastErrors()

answered Apr 4, 2011 at 8:21

jeremyFreeAgent

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Comments

powtac · Accepted Answer · 2011-04-04 15:13:33Z

-2

change

$date = DateTime::createFromFormat('Y-m-d', $badDate);

into

$date = DateTime::createFromFormat('Y-d-m', $badDate);

Your given format is wrong, you properly mixed up days and months...

To understand what is behind the magical calculation of dates read this very very good article by Derick Rethans and all comments ;)

edited Apr 4, 2011 at 15:13

answered Apr 4, 2011 at 8:40

powtac

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5 Comments

Clement Herreman Over a year ago

The format isn't wrong, it really is `Y-m-d', I want to ensure that date validity is checked.

powtac Over a year ago

But when m is the second part and you pass 13: its calculated as January in the next year. Everything is fine here! This is the way PHP calculates with overlapping numbers on dates.

Clement Herreman Over a year ago

Indeed, that's what I just discovered, but 2 questions rise : 1. where the hell is it documented ? 2. Am I the only that doesn't find this behavior logical/expectable ?

powtac Over a year ago

I added a link to an article.

Clement Herreman Over a year ago

Nice article, but maybe you should also edit your answer about me using a bad format =).

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