Return headers in output when running "php -f index.php"

Question

I tried searching around to find an answer to this but to no avail.

I have a simples PHP script with the below code:

<?php
header("Content-Type: application/json");
echo "Hello";
?>

I then execute the file using the below command:

php -f index.php

and the output is:

Hello

My question is, is it possible to return the header I outputted using PHP, so my expected output would be something like:

Content-Type: application/json

Hello

@mario Thanks! I tried php-cgi but with the -f option, removed and it works! — Ben Osborne
– Ben Osborne, Commented Apr 3, 2019 at 12:40

Ben Osborne · Accepted Answer · 2019-04-03 12:43:16Z

1

You can achieve this by using php-cgi without the -f option:

php-cgi index.php

X-Powered-By: PHP/7.3.3
Content-Type: application/json

Hello

answered Apr 3, 2019 at 12:43

Ben Osborne

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