How to put php variable in img src?

Question

I don't know why it doesn't work I am trying to view profile image. the path is in database and $data['pic'] shows the path but I think the syntax is wrong Thx in advance :)

<img src="/images/<?php echo $data['pic']->pic_path; ?>">

This is var_dump($data['pic']) as you see you see pic_path has a value in it

object(Profile_model)#3 (12) { ["user_id"]=> NULL ["username"]=> NULL ["f_name"]=> NULL ["l_name"]=> NULL ["phone"]=> NULL ["email"]=> NULL ["address"]=> NULL ["height"]=> NULL ["weight"]=> NULL ["goal"]=> NULL ["_connection":protected]=> object(PDO)#4 (0) { } ["pic_path"]=> object(Profile_model)#8 (12) { ["user_id"]=> NULL ["username"]=> NULL ["f_name"]=> NULL ["l_name"]=> NULL ["phone"]=> NULL ["email"]=> NULL ["address"]=> NULL ["height"]=> NULL ["weight"]=> NULL ["goal"]=> NULL ["_connection":protected]=> object(PDO)#9 (0) { } ["pic_path"]=> string(27) "5caf5df7b2ee68.41908466.jpg" } }

<img src="/images/<?php echo $data['pic']->pic_path; ?>">

Francinaldo Almeida · Accepted Answer · 2019-04-12 00:59:40Z

3

From what you provided in your question, I can see that $data['pic']->pic_path is an object of type Profile_model, and inside of it, there is another property 'pic_path' which is, in fact, a string. So I believe $data['pic']->pic_path->pic_path would give you the path, but I suspect this is not the intended behavior. I would suggest you double check how an object is being assigned to the first $data['pic']->pic_path.

answered Apr 12, 2019 at 0:59

Francinaldo Almeida

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5 Comments

Nick Over a year ago

You raise a good point about the original assigment to $data['pic']->pic_path.

Hongsuk Choi Over a year ago

Thank you so much for the comment, now it finally works but why pic_path is an object? is it because how I sent to view ?

Hongsuk Choi Over a year ago

$this->view('profile/index_profile', ['profile'=>$profile,'pic'=>$pic]);

Hongsuk Choi Over a year ago

This is how I sent the data from controller to view

Francinaldo Almeida Over a year ago

I wouldn't say it has to do with the way you send it to the view (suspect you are using Laravel). It is more what value $pic is being assigned before being sent to the view. If you can update your question with the controller code I can try to help you with that.

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