Putting the Digits of an int into an Array using Java?

Question

I want to separate int values that are provided via user input. For example, when entering 153 I want to extract each digit (3 then 5 then 1 or vice versa) and stick all of them into an int[].

So far I have used the modulus operator to extract the last digit, but I still need to extract all the previous digits so I can proceed to test whether the int given by the user is narcissistic or not.

The reason for doing this is so that I can test whether the user has inputted a narcissistic number. The program will return true or false depending on the input.

public class narc {

    public static void main(String[] args){
         Scanner myScan = new Scanner(System.in);
         System.out.println("enter number: ");
         int digit = myScan.nextInt();
         String s1 = Integer.toString(digit);
         System.out.println(narcNumber(digit));
   }

   public static boolean narcNumber(int number) {
       System.out.println(number%10);
       return false;
   }
}

So far, narcNumber(num) only returns the last digit of the given number.

I now need to extract all other numbers input by the user separately -- Use a loop for it. Plenty of solutions out there on the net to achieve this. — Nicholas K
– Nicholas K, Commented Apr 19, 2019 at 14:08
For other digits in a single number, you can just read the number as a string, and use String.charAt() to extract the digits. — markspace
– markspace, Commented Apr 19, 2019 at 14:10

devgianlu · Accepted Answer · 2019-04-19 14:09:56Z

3

int[] split = new int[s1.length()];
for (int i = 0; i < split.length; i++) {
    split[i] = Character.getNumericValue(s1.charAt(i));
}

split will contain all numbers of the input number.

answered Apr 19, 2019 at 14:09

devgianlu

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vincrichaud · Accepted Answer · 2019-04-22 20:49:28Z

0

If you still want to use modulus to get the digits :

List<Integer> digits = new ArrayList<Integer>();
while(inputNumber > 0) {
    currentDigit = inputNumber % 10;
    digits.add(currentDigit);
    inputNumber = inputNumber / 10;
}

edited Apr 22, 2019 at 20:49

answered Apr 19, 2019 at 14:22

vincrichaud

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