Does assigning a variable to a function call actually call the function then or just store it (so it's ready to be called)?
For example does:
val userData = GraphRequest.newMeRequest(
accessToken,
object : GraphRequest.GraphJSONObjectCallback {
override fun onCompleted(`object`: JSONObject?, response: GraphResponse?) {
Log.d(TAG, `object`.toString())
}
}
)
actually call GraphRequest.newMeRequest()?
Yes, that code first calls GraphRequest.newMeRequest(), and assigns its result to userData.
In general, any time you see parens after a function name (or lambda), that will call the function.
If you want a reference to the function without calling it (e.g. to call later, or to return or pass to another function), you can use GraphRequest::newMeRequest. You'll then need to pass the relevant arguments when you call it.
More info here.
Yes, that will call the GraphRequest.newMeRequest(..) method and assign the result to userData immediately. If you want the field to be initialized at a later time, but only when the field is first accessed, use a lazy delegate.
val userData by lazy { /* call method */ }
