How to extract parameter and values from a string using regex

Question

I need to extract a param and the value for that param from a string ((created_date{[1976-03-06T23:59:59.999Z TO *]}|1)). Here param is created_date. Value is 1976-03-06T23:59:59.999Z TO * where * denotes no restriction. I need to extract the data as shown below i,e it should be an array of string.

created_date
1976-03-06T23:59:59.999Z
*
1

I have tried some online regex tool to find a suitable regex and also tried some code on trial and error basis.

String str = "((created_date{[1976-03-06T23:59:59.999Z TO *]}|1))";
String patt = "\\((.*)\\{(.*)\\}\\|(1|0)\\)";
Pattern p = Pattern.compile(patt);
Matcher m = p.matcher(str);
MatchResult result = m.toMatchResult();
System.out.println(result.group(1));

similary result.group(2) and 3.. depending on the result.groupCount().

I need to extract the data as shown below i,e it should be an array of string.

created_date

1976-03-06T23:59:59.999Z

*

1

Aaron · Accepted Answer · 2019-07-02 12:33:25Z

1

You can use the following :

String str = "((created_date{[1976-03-06T23:59:59.999Z TO *]}|1))";
String patt = "\\(\\(([^{]+)\\{\\[([^ ]+) TO ([^]]+)]}\\|([01])\\)\\)";
Pattern p = Pattern.compile(patt);
Matcher m = p.matcher(str);
if (m.matches()) {
    System.out.println(m.group(1));
    System.out.println(m.group(2));
    System.out.println(m.group(3));
    System.out.println(m.group(4));
}

Try it here !

Note that you need to invoke a Matcher's find(), matches() or more rarely lookingAt() before you can use most of its other methods, including the toMatchResult() you were trying to use.

answered Jul 2, 2019 at 12:33

Aaron

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