Find & Replace with given array elements?

Question

Given the following:

String: "{Dog} loves {Cat}",

RegExp: {([^}]+)},

Array: ["Scooby Doo", "Sylvester"]

How can I easily achieve: "Scooby Doo loves Sylvester"

Thank you @WiktorStribiżew it works pretty nice. Looking for the documentation to understand this beautiful "magic" ... — Michael Pacheco
– Michael Pacheco, Commented Jul 7, 2019 at 19:36
Got it! All you have done is replacing matches by {} and then using string replacing in python 3 style. Pretty nice trick! — Michael Pacheco
– Michael Pacheco, Commented Jul 7, 2019 at 19:41

Wiktor Stribiżew · Accepted Answer · 2019-07-07 19:41:48Z

1

You may replace each substring inside curly braces with a {} substring that acts as a placeholder when the string is passed to str.format method. The list needs to be "cast" to a sequence of variables (it is called unpacking), thus, the prefix operator * is required before the list passed to str.format.

So, the code can look like

import re
s = "{Dog} loves {Cat}"
l = ["Scooby Doo", "Sylvester"]
print(re.sub(r'{[^{}]*}', '{}', s).format(*l))
# => Scooby Doo loves Sylvester

See the Python demo.

answered Jul 7, 2019 at 19:41

Wiktor Stribiżew

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