How to run bash file for (different directory) as input automatically

Question

I have a bash file which takes 5 inputs.

Input1 = file1
Input2 = file2
Input3 = directory1
Input4 = func
Input5 = 50

input 4 and 5 are always the same, never change.

file1 and file 2 are located inside directory1

directory1 is located inside a code directory

/code/directory1/file1
/code/directory1/file2

and there are many directories with the same structure directory(1-70) inside the code folder

/code/directory1/*
/code/directory2/*
/code/directory3/*
...
/code/directory70/*

In order to run the bash file, I have to run the command from terminal 70 times :<

Is there a way to automatically run all these folders at once?

UPDATE: the directory(1-7) each one has a different name e.g bug1, test, 4-A and so on. Even the files are different e.g. bug1.c hash.c

/code/bug1/bug1.c
code/bug1/hash.c

for d in /code/directory* ; do yourscript.sh $d/file1 $d/file2 $d func 50 ; done, assuming that file1 and file2 are in all these directories. — January
– January, Commented Jul 23, 2019 at 9:48
Also check out the find command if you need something more complex than a single directory wildcard. — Gem Taylor
– Gem Taylor, Commented Jul 23, 2019 at 13:37

sungtm · Accepted Answer · 2019-07-23 13:57:02Z

1

Try this:

for dirs in $(ls -F /code | grep '/')
do
    eval files=( "$(ls -1 ${dirs})" )
    <ShellScript>.sh "${dirs}${files[0]}" "${dirs}${files[1]}" "${dirs%/}" func 50
done

edited Jul 23, 2019 at 13:57

answered Jul 23, 2019 at 13:50

sungtm

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