symfony framework

Question

I'm using this validation code in actions.class.php to validate the input ,

$name = $this->getRequestParameter('title');    
if (!$name)
{
    $this->getRequest()->setError('The name field cannot be left blank');
    return false;
}

But encounter errors like

You must set "compat_10" to true if you want to use this method which is deprecated.

in error log. After getting this error, I set compat_10 to true in settings.yml, but still get the same error.

Are you not using the form framework? You can set validators on form fields using that. — terrid25
– terrid25, Commented Apr 21, 2011 at 12:09

Trak · Accepted Answer · 2013-08-29 22:49:36Z

1

The $this->getRequest()->setError() method is only available in symfony 1.0 and 1.1, strating from symfony 1.2 the validator behaviour and all the error handling in the actions was removed in order to be more in line with the new form framework.

I'm guessing you're using a version 1.2 to 1.4, in which case the method you're trying to use is deprecated and you have to enable the compat_10 plugin for that. I see that you have enabled it but since it's behavior comes from a plugin you must ensure that you have sfCompat10Plugin enabled in your ProjectConfiguration::configure() method.

As a side note, it's best to use the validators form the form framework for this kind of errors.

answered Aug 29, 2013 at 22:49

Trak

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Comments

Grad van Horck · Accepted Answer · 2011-04-21 12:35:45Z

0

Depending on how hard you want to fail you can do one of the following:

Throw a sfException... This shows the generic 500 error message.
forward to 404. For example when your title is part of the url or an other sort of selection parameter. There's a handy way to do this: $this->forward404Unless($name, 'No title provided').
Set your message to template var $this->errorMessage = '...'; and then return the error view return sfView::ERROR, and show a nice message in the template actionError.php.

(I'd probably go for the second)

answered Apr 21, 2011 at 12:35

Grad van Horck

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Comments

Suresh Kumar Amrani · Accepted Answer · 2013-02-28 16:45:04Z

0

You can use exceptional handling for error handling

try {
 $this->getRequest()
 } catch (\Doctrine\ORM\NoResultException $e) {
 return null;
}

answered Feb 28, 2013 at 16:45

Suresh Kumar Amrani

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1 Comment

j0k Over a year ago

This is for doctrine2 and / or symfony 2, OP talks about symfony 1

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