python regex match and replace dates

Question

I need to match dates in form:

January 10, 2012

And replace in form:

10 January 2012

Here is what I have so far:

        pattern = re.findall(r'(?:January|February|March|April|May|June|July|August|September|October|November|December)\s\d\d,\s\d{4}', text)
        print pattern

How do i replace?

What have you tried? Please post your code and any specific problems you're having. — S.Lott
– S.Lott, Commented Apr 25, 2011 at 21:00
@Doug T. - Even if it's not, it's still not a passable question. As it stands, the question appears to be "I don't know regular expressions, write one for me." — Chris Lutz
– Chris Lutz, Commented Apr 25, 2011 at 21:01
Yes I need help convert from form January 10, 2012 to form 10 January 2012 — michael
– michael, Commented Apr 25, 2011 at 21:01
@michael: "replace" is entirely the wrong concept. You're just formatting the output. — S.Lott
– S.Lott, Commented Apr 25, 2011 at 21:09

ThiefMaster · Accepted Answer · 2011-04-25 21:08:25Z

5

Use strptime() to parse the date and strftime() to generate the new string. There is no reason to use a regex in this case.

In [1]: import time
In [2]: tm = time.strptime('January 10, 2012', '%B %d, %Y')
In [3]: time.strftime('%d %B %Y', tm)
Out[4]: '10 January 2012'

edited Apr 25, 2011 at 21:08

answered Apr 25, 2011 at 21:03

ThiefMaster

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Comments

user557597 · Accepted Answer · 2011-04-25 21:07:27Z

0

Just in general, something like this:

find: ^(January) (\d{1,2}), (\d{4})$ replace $2 $1 $3

answered Apr 25, 2011 at 21:07

user557597

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