Python - executing two functions in parallel

Question

I'm very new to python and I have following problem. I'm trying to divide a variable (counta) by 3 and get the result every 10 seconds. At the same time I want to add 1 to the counter every time I press 'a'. The problem is that I'm using a method where I can only add 1 every 10 seconds. Please can you advise what could be changed so that I could add 1 whenever I like and i still get the current result (counta/3). Thank you in advance for your help. This is my code so far:

from pynput.keyboard import Listener
import sched, time 




counta = 0
Timer = 0




def on_press(key):


    if key.char == 'a':
        #print("")
        global counta
        counta += 1
        #print("Aktuell" + str(counta))

    elif key.char == 'p':
        print(int(counta/3))

    elif key.char == 's':
        Stand(counta, Timer)


    else:
        print("Falsche Taste!")
        print("a = counta")


def Stand(counta, Timer):
    while Timer < 10: 
        print(str(counta/3))
        time.sleep(1)
        Timer += 1




with Listener(on_press=on_press) as listener:
    listener.join()

You need to read up on the Threading package. It allows you to execute a function in a thread in parallel with other functions. — Simon Notley
– Simon Notley, Commented Sep 18, 2019 at 10:17
you have to use Listener in differen way. Create listener = Listener(on_press=on_press) before while loop, and use listener.join() after while loop — furas
– furas, Commented Sep 18, 2019 at 10:20

furas · Accepted Answer · 2019-09-18 22:08:24Z

2

You can use Listener in different way

listener = Listener(on_press=on_press)
listener.start()

while Timer < 10: 
    print(str(counta/3))
    time.sleep(1)
    Timer += 1

#listener.stop()
listener.join()

or using your function

listener = Listener(on_press=on_press)
listener.start()

Stand(counta, Timer)

#listener.stop()
listener.join()

BTW: class Listener already uses thread to listen keys - class Listener(threading.Thread):.

EDIT: I released that you can also use it this way

with Listener(on_press=on_press) as listener:

    while Timer < 10: 
        print(str(counta/3))
        time.sleep(1)
        Timer += 1

    #listener.stop()
    listener.join()

or using your function

with Listener(on_press=on_press) as listener:

    Stand(counta, Timer)

    #listener.stop()
    listener.join()

edited Sep 18, 2019 at 22:08

answered Sep 18, 2019 at 10:22

furas

149k12 gold badges121 silver badges171 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

furas Over a year ago

I added example which uses with Listener()

Calvin-Ruiz · Accepted Answer · 2019-09-18 10:20:30Z

0

The easiest way is to use a Tread :

import treading # at begin of your file


thread = threading.Thread(target=Stand) # create thread with your function
thread.start() # launch your function

Note that print method can reduce time execution of your function, and print in thread won't be recommended.

answered Sep 18, 2019 at 10:20

Calvin-Ruiz

1721 gold badge2 silver badges11 bronze badges

Collectives™ on Stack Overflow

Python - executing two functions in parallel

2 Answers 2

1 Comment

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

1 Comment

Comments

Your Answer

Sign up or log in

Post as a guest

Related