How to dereference and print each element of a pointer array?

Question

Let's say I have an array of pointers:

struct S {int x;};
S *arr[3] = {new S{1}, new S{2}, new S{3}};

I want to make gdb dereference and print each element of the array.

Printing one element is simple:

(gdb) p *arr[0]                                                                                            
$1 = {x = 1}

but I want to print every element in the array in this fashion.

I tried p arr, but it outputs the pointers, rather than the objects they point to:

(gdb) p arr
$1 = {0x613c20, 0x613c40, 0x613c60}

Picaud Vincent · Accepted Answer · 2019-10-19 16:50:22Z

2

I have not found better than that:

(gdb) set $i=0
(gdb) p *arr[$i++]
$102 = {x = 1}
(gdb) 
$103 = {x = 2}
(gdb) 
$104 = {x = 3}
(gdb)

maybe it can help.

note: simply press return to show the next value.

answered Oct 19, 2019 at 15:26

Picaud Vincent

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2 Comments

can i use for in gdb?

thank you,i have sovled all problem,because i can use while in gdb,and it can comletely sovle the problem,although its little complex