VimL/Vimscript: how to access local variable of outer function from its inner function?

Question

I have a function of the following form:

function! s:my_function(dict_arg)
    let darg = copy(a:dict_arg)

    func! my_inner_func(cond)
        if a:cond ==# 'a'
            execute darg.a
        elseif a:cond ==# 'b'
            execute darg.b
        elseif a:cond ==# 'c'
            execute darg.c
        endif
    endfunc

    return function('my_inner_func')
endfunc

Where the argument passed to the dict_arg parameter will be some dict keyed with a, b and c, with their respective values being strings representing Ex commands that will be executed depending on the specific cond (condition).

The purpose of the outer function s:my_function is to generate a Funcref that will execute the appropriate Ex command (darg.a, darg.b or darg.c) based on the cond, which is itself determined elsewhere by other variables.

So my problem is that I don't know how to reference the local variable darg defined in the scope of s:my_function from within my_inner_func. When the function is called, I get the error E121: Undefined variable: darg. It also doesn't work (same error) if I don't define the local variable darg, and instead just try to do execute a:dict_arg.b for instance.

I can get around it by defining darg to be global, as in let g:darg = copy(a:dict_arg), then later doing execute g:darg.a. But of course, I'd like to avoid that.

In something like Python, this type of lexical scope resolution is automatic. But VimL is well.. VimL. Any help or pointers will be appreciated.

Matt · Accepted Answer · 2019-11-07 06:28:34Z

3

In something like Python, this type of lexical scope resolution is automatic

In VimScript, except lambdas, it's manual. You have to explicitly add closure keyword:

func! my_inner_func(cond) closure
    ...
endfunction

The purpose of the outer function s:my_function is to generate a Funcref that will execute the appropriate Ex command (darg.a, darg.b or darg.c) based on the cond, which is itself determined elsewhere by other variables.

IMO, it's better to use "a partial".

function! InnerFunc(foo, bar, baz)
    ...
endfunction
...
let OuterFunc = function('InnerFunc', ["FOO", "BAR"])
call OuterFunc("BAZ")

answered Nov 7, 2019 at 6:28

Matt

15.4k1 gold badge25 silver badges31 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

VimL/Vimscript: how to access local variable of outer function from its inner function?

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related