For loop in PHP with a unique output for only one loop

Question

I have a project where I have inputs that decide the range of numbers echoed but I also need to have a single number echo more text. At the moment I have an if statement which works but echoes the number a second time.

for ($x = $var1; $x <= $var2; $x += $varInc) {
    echo "<p>$x</p>";
    if ($x == $varGhost){
        echo "<p class='fas fa-ghost'></p>";
    }
}

It's supposed to look similar to this:

It echoes the number a second time? It doesn't look like it would do that. — Don't Panic
– Don't Panic, Commented Nov 15, 2019 at 0:23

Szymek · Accepted Answer · 2019-11-15 00:05:54Z

2

You should change your code to:

for ($x = $var1; $x <= $var2; $x += $varInc) {
 if ($x == $varGhost){
    echo "<p>$x - GHOST!</p>";
 } else {
    echo "<p>$x</p>";
 }
}

I hope it works :)

answered Nov 15, 2019 at 0:05

Szymek

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Comments

Alessandro Tedesco · Accepted Answer · 2019-11-15 00:27:47Z

It isn't working as expected because the second line echoes the number $x in any case, regardless the following if statement:

for ($x = $var1; $x <= $var2; $x += $varInc) {
    echo "<p>$x</p>"; // this line echoes the number $x in any case
    if ($x == $varGhost) {
        echo "<p class='fas fa-ghost'></p>";
    }
}

You should check the value of $x before printing it like this:

for ($x = $var1; $x <= $var2; $x += $varInc) {
    if ($x == $varGhost) {
        echo "<p class='fas fa-ghost'></p>";
    }
    else {
        echo "<p>$x</p>"; // this line echoes the number $x ONLY if it isn't a ghost
    }
}

Anyway, a shorter way to write it:

for ($x = $var1; $x <= $var2; $x += $varInc)
    echo ($x == $varGhost) ? "<p class='fas fa-ghost'></p>" : "<p>$x</p>"

Hope it helps :)

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