dynamic name for a file in Python

Question

I have a subject_id which is a dynamic number.For instance, it could be equal to 60. I am manually defining some file names as follows: x_file = "50.txt" x_csv_file = "50.csv" The number (50) could have been 1 or any-number else. Is there any way that I can define subject_id=50 JUST one time and then use those names as x_file = "subject_id.txt" and x_csv_file = "subject_id.csv"?. Thanks For your help

You'll probably want to save subject_id='50' and then do x_file=subject_id + '.txt' and x_csv_file=subject_id + '.csv: The + between two strings acts as the concatenation operator, hence the strings are pasted together to produce your desired output — Lukas Thaler
– Lukas Thaler, Commented Dec 5, 2019 at 21:52
Thank you for your help. But it gives me the following error:TypeError: unsupported operand type(s) for +: 'int' and 'str — Nevi
– Nevi, Commented Dec 5, 2019 at 21:58
@LukasThaler Thanks Lukas. You are right! Thank you for your help — Nevi
– Nevi, Commented Dec 5, 2019 at 22:07

wilson tao · Accepted Answer · 2019-12-05 21:56:54Z

1

You might want to define a simple function for this

def file_name(subject_id):
    x_file = '{}.txt'.format(subject_id)
    x_csv_file = '{}.csv'.format(subject_id)
    return x_file, x_csv_file

answered Dec 5, 2019 at 21:56

wilson tao

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3 Comments

Nevi Over a year ago

Worked as a charm!

wilson tao Over a year ago

You can do x_csv_file = str(subject_id) + '.csv' with Lukas' solution too : )

AMC Over a year ago

Why not use f-strings?

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