problem with image in php

Question

I want to show an image and wrote below codes

$path = "C:\xampp\htdocs\me\1.jpg";
$image1 = imagecreatefromjpeg($path);
header('Content-Type: image/jpeg');
imagejpeg($image1);

But when I run it in Firefox it shows:

The image “http://127.0.0.1/me/Untitled%201.php” cannot be displayed because it contains errors.

What is problem?

Edit:

I deleted header function but it has this error:

Warning: imagecreatefromjpeg(C: mpp\htdocs\me.jpg) [function.imagecreatefromjpeg]: failed to open stream: Invalid argument in C:\xampp\htdocs\me\Untitled 1.php on line 136

Warning: imagejpeg() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\me\Untitled 1.php on line 138

after all works it shows some chars like this

    $.' ",#(7),01444'9=82<.342ÿÛC  2!!22222222222222222222222222222222222222222222222222ÿÀ¸)"ÿÄ ÿÄµ}!1AQa"q2‘¡#B±ÁRÑð$3br‚ %&'()*456789:CDEFGHIJSTUVWXYZcdefghijstuvwxyzƒ„…†‡ˆ‰Š’“”•–—˜™š¢£¤¥¦§¨©ª²³´µ¶·¸¹ºÂÃÄÅÆÇÈÉÊÒÓÔÕÖ×ØÙÚáâãäåæçèéêñòóôõö÷øùúÿÄ ÿÄµw!1AQaq"2B‘¡±Á #3RðbrÑ $4á%ñ&'()*56789:CDEFGHIJSTUVWXYZcdefghijstuvwxyz‚ƒ„…†‡ˆ‰Š’“”•–—˜™š¢£¤¥¦§¨©ª²³´µ¶·¸¹ºÂÃÄÅÆÇÈÉÊÒÓÔÕÖ×ØÙÚâãäåæçèéêòóôõö÷øùúÿÚ?ùþŠ( Š( Š( Š( Š( Š( Š( Š( Š( Š( Š( Š( Š( Š( Š( Š

the problem was solved by removing <html> tags

Mahdi_Nine
– Mahdi_Nine

2011-05-07 12:51:06 +00:00
Commented May 7, 2011 at 12:51 — Mahdi_Nine
– Mahdi_Nine, Commented May 7, 2011 at 12:51

Pekka · Accepted Answer · 2011-05-07 11:20:43Z

2

In this specific case, you forgot to escape the backslashes \ in the file path. Either use escaped backslashes \\ or - much better - forward slashes: /

   $path = "C:/xampp/htdocs/me/1.jpg";

To debug stuff like this, remove the header() line to see the image's source code to see the PHP error messages that are breaking it.

answered May 7, 2011 at 11:20

Pekka

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4 Comments

Joshua - Pendo Over a year ago

Was going to say that. On windows servers I usually use c:\\folder\\folder2\\file.ext single slashes don't work unless you use forward slashes or double backslashes. It's also clearly visible in your error, it states C: xampp instead of C:\xampp

Pekka Over a year ago

@mehdi did you put the header back in after fixing the problem? Removing the header is meant for debugging purposes only. To see the image, you need the header.

Mahdi_Nine Over a year ago

The image “127.0.0.1/me/Untitled%201.php” cannot be displayed because it contains errors.

Pekka Over a year ago

Strange. So there is no human-readable error message in the peculiar characters? If 1.jpg indeed is a valid JPG file, I don't know what this is then.

Robik · Accepted Answer · 2011-05-07 11:21:11Z

1

You image contains errors, what errors? Try temponary removing header() functions.

$path = "C:\xampp\htdocs\me\1.jpg";
$image1 = imagecreatefromjpeg($path);
#header('Content-Type: image/jpeg');
imagejpeg($image1);

answered May 7, 2011 at 11:21

Robik

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Comments

publikz.com · Accepted Answer · 2011-05-07 11:28:50Z

1

(C: mpp\htdocs\me.jpg)

As yor see this differs from

(C:\mpp\htdocs\me.jpg)

So your need change your code:

$path = "C:/xampp/htdocs/me/1.jpg";
$image1 = imagecreatefromjpeg($path);
header('Content-Type: image/jpeg');
imagejpeg($image1);

Or like this:

$path = 'C:\xampp\htdocs\me\1.jpg';
$image1 = imagecreatefromjpeg($path);
header('Content-Type: image/jpeg');
imagejpeg($image1);

Also to debug:

Remove header.
Make echo ...

:

$path = 'C:\xampp\htdocs\me\1.jpg'; <-- single quoted
echo $path;
$image1 = imagecreatefromjpeg($path);
//header('Content-Type: image/jpeg'); <-- commented
imagejpeg($image1);

Arsen

answered May 7, 2011 at 11:28

publikz.com

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1 Comment

Steve-o Over a year ago

@mehdi that's the expected output.

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