printf string, variable length item

Question

#define SIZE 9
int number=5;
char letters[SIZE]; /* this wont be null-terminated */
... 

char fmt_string[20];
sprintf(fmt_string, "%%d %%%ds", SIZE);
/* fmt_string = "%d %9d"... or it should be */

printf(fmt_string, number, letters);

Is there a better way to do this?

You seem to be building a format string. But you should be assigning the string returned by sprintf to fmt_string and fmt_string shouldn't be in the parameter list. — pavium
– pavium, Commented May 9, 2011 at 3:41
Is there any particular reason you say that letters won't be null-terminated? — Andrew Keeton
– Andrew Keeton, Commented May 9, 2011 at 3:53
@AndrewKeeton this was for a search problem with a large dataset where I couldn't afford the space to hold null characters. — William Entriken
– William Entriken, Commented Oct 11, 2014 at 19:46
NOTE: this is a duplicity of stackoverflow.com/questions/2239519/… — pevik
– pevik, Commented Sep 2, 2016 at 8:31

mah · Accepted Answer · 2018-02-01 08:36:43Z

136

There is no need to construct a special format string. printf allows you to specify the precision using a parameter (that precedes the value) if you use a .* as the precision in the format tag.

For example:

printf ("%d %.*s", number, SIZE, letters);

Note: there is a distinction between width (which is a minimum field width) and precision (which gives the maximum number of characters to be printed). %*s specifies the width, %.s specifies the precision. (and you can also use %*.* but then you need two parameters, one for the width one for the precision)

See also the printf man page (man 3 printf under Linux) and especially the sections on field width and precision:

Instead of a decimal digit string one may write "*" or "*m$" (for some decimal integer m) to specify that the precision is given in the next argument, or in the m-th argument, respectively, which must be of type int.

edited Feb 1, 2018 at 8:36

mah

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answered May 9, 2011 at 4:07

Trent

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5 Comments

William Entriken Over a year ago

Had them mixed up... scanf is the one that doesn't have that option.

ott-- Over a year ago

It also works with 2 lengths like "%*.*s", minlength, maxlength, letters.

chux Over a year ago

Note: "*m$" is not standard C.

Jimmay Over a year ago

Is there a way to get the "%.*s" format to accept size_t instead of int?

piedramania Jul 17 at 10:05

make a cast to (int)var_size_t

Cristian Ciupitu · Accepted Answer · 2014-10-14 01:11:12Z

6

A somewhat unknown function is asprintf. The first parameter is a **char. This function will malloc space for the string so you don't have to do the bookkeeping. Remember to free the string when done.

char *fmt_string;

asprintf(&fmt_string, "%%d %%%ds", SIZE);
printf(fmt_string, number, letters);
free(fmt_string);

is an example of use.

edited Oct 14, 2014 at 1:11

Cristian Ciupitu

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answered May 9, 2011 at 3:49

No One in Particular

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2 Comments

Trent Over a year ago

Although asprintf is indeed an interesting function, it is important to note that it is a gnu extention. Also, I'm not sure how this addresses the question.

Cristian Ciupitu Over a year ago

@Trent, it's true that it started as a GNU extension, but in the mean time OpenBSD, FreeBSD and NetBSD have implemented it. Even Mac OS X has it now.

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