Accessing a function of an anonymous class in Python

Question

I am a beginner in Python and have gone through some help material on __ symbol and my question is based on it.

I have executed the following in a Python 3.7 shell / interpreter:

 class __:

...     def strangeClassName():

...             print("Inside a function")

…

 inst = __()

which is not problematic at all. However, when I try to access the print statement using the function name(strangeClassName()), I am not able to get it. I mean - not able to see the print's output.

What is happening and how to access the function, as the call inst.strangeClassName did not help!

Bogdan · Accepted Answer · 2020-01-10 11:47:01Z

5

You must specify the first argument that represents the instance object for all instance methods. The name self is only convention and you can name it your way. But following the convention is the good practice.

Looks like this:

class __:
    def foo(self):
        print("inside")


inst = __()
inst.foo()

Output:

inside

edited Jan 10, 2020 at 11:47

answered Jan 10, 2020 at 11:13

Bogdan

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1 Comment

Karri Chandrasekhar Over a year ago

Thanks for your response. So, can I consider passing 'self' to every method as a best practice & is a must for instance methods (as against static methods) ?

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