How replace strings after specific character?

Question

i'm trying to delete all strings after || in the following list:

mylist=[' # - || CAICEDO','LoL','lora',' moco','Sar || var']

For that, i'm using:

def limp_2(n):
         return re.sub(r'^(\w+)-([\||\.])(.+)','',n)

clean_2=list(filter(limp_2,clean_1))
print(clean_2)

The idea is to get:

mylist=[' # - ','LoL','lora',' moco','Sar']

Instead, I just have the same list. That is just an example, I want to apply that to a large list.

I'll appreciate your help.

Why is that you don't want to alter first element, but everything after || in some element of the list are removed ? — Austin
– Austin, Commented Feb 2, 2020 at 4:59
Just use return n.split("||")[0].strip() if you want to do what you asked - see rextester.com/ZYOHO99856 — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Feb 2, 2020 at 9:14
I would like to understand what have you make, what meands [0].strip and how is related with .split. I haven't found the part in [] as a parameter for .split. Thanks again. — HAAB
– HAAB, Commented Feb 2, 2020 at 14:37

Jordan Brière · Accepted Answer · 2020-02-02 05:15:24Z

1

You don't need to use a regex for that. You could simply use something like:

mylist = ['   #  - || CAICEDO', 'LoL', 'lora', ' moco', 'Sar || var']

clean_2 = [mylist[0]] + [s.split('||', 1)[0].rstrip() for s in mylist[1:]]

print(clean_2)

Result:

['   #  - || CAICEDO', 'LoL', 'lora', ' moco', 'Sar']

edited Feb 2, 2020 at 5:15

answered Feb 2, 2020 at 5:08

Jordan Brière

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