how to extract hex value from string by python?

Question

below is string Register addr = [0x0128], data = [0x59]

i want to get 0x59 not 0x0128 by using Regex

this is my code

import re
data = "Register addr = [0x0128], data = [0x59]"
pattern = re.compile("d[.]]")
re.findall(pattern, data)

i don't have idea to get exact 0x59 could you help me?

is 0x59 the only string you wanna extract? or it may change? — Mox
– Mox, Commented Feb 21, 2020 at 2:17
is 0x59 always followed by word 'data' & '=' and within square brackerts? — moys
– moys, Commented Feb 21, 2020 at 2:17
Reverse the string, reverse the pattern, extract the first match. Or use finditer/findall with a appropriate pattern and keep the last. Maybe r'(0x[^\]]+)' — wwii
– wwii, Commented Feb 21, 2020 at 2:26

moys · Accepted Answer · 2020-02-21 02:29:36Z

3

You can do

data = "Register addr = [0x0128], data = [0x59]"
print(re.findall(r'(?<=data\s=\s)\[(\w*)\]',data))

Output

['0x59']

you can also do print(re.search(r'(?<=data\s=\s)\[(\w*)\]',data).group(1))

output

Note that re.search returns ONLY the first match (it stops serching after the first match has been found.

0x59

edited Feb 21, 2020 at 2:29

answered Feb 21, 2020 at 2:19

moys

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Comments

PacketLoss · Accepted Answer · 2020-02-21 02:21:14Z

1

If you're only seeking to find 0x59 just do a direct search for it.

pattern = re.compile(r"0x59")

If you want to find all hex codes beginning with 0x located within []

pattern = re.compile(r"\[0x.*?\]")
re.findall(pattern, data)
#['[0x0128]', '[0x59]']

answered Feb 21, 2020 at 2:21

PacketLoss

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Comments

NotLost · Accepted Answer · 2020-02-21 02:25:59Z

1

The easy way to do it is via:

print(re.sub(']', '', data.partition("data = [")[2]))

.partition splits the string on data = [ giving a tuple & [2] selects the part of the string after data = [.

re.sub removes all of the ] from that string.

Note, both 0x59 and 0x0128 are valid hex numbers.

answered Feb 21, 2020 at 2:25

NotLost

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