create table employee
(emp_id integer not null,
manager_id integer not null,
emp_name char(20) not null,
emp_tel char(10),
emp_salary number not null,
hire_date date,
constraint pk_employee primary key(emp_id)
);
alter table employee
add constraint fk_employee_manager foreign key(manager_id)
references employee(emp_id);
Need help to Find the ID of managers that have more than 5 employees working with them.
just do this: You need to familialrize yourself with the possibilities of grouping functions
select manager_id
from employee
group by manager_id
having count(*)>5
insert into employee (emp_id, manager_id, emp_name, emp_salary)
select 1, 1, 'A', 1000 from dual
union select 2, 1, 'A', 1000 from dual
union select 3, 1, 'A', 1000 from dual
union select 4, 1, 'A', 1000 from dual
union select 5, 1, 'A', 1000 from dual
union select 6, 1, 'A', 1000 from dual
union select 7, 2, 'A', 1000 from dual;
select manager_id, count(emp_id) from employee group by manager_id
having count(emp_id) > 5;
