How can I perform calculations in python using two lists? Where the first calculation would be, c = -(1)/cos(4), second being, c = -(5)/cos(6), etc
import numpy as np
x, y = [1,5,2,1], [4,6,2,3]
c = []
c = -x/(np.cos(y))
print(c)
When I try this I currently get the error :
TypeError: bad operand type for unary -: 'list'
This can be done without numpy:
from math import cos
x, y = [1,5,2,1], [4,6,2,3]
c = [-i/cos(j) for i,j in zip(x,y)]
You have to cast the list to numpy array.
c = -np.array(x)/(np.cos(y))
print(c)
now you will have the results store in the np array
array([ 1.52988566, -5.20740963, 4.80599592, 1.01010867])
or if you want a list again
c = list(c)
You can iterate over the length of the list:
import numpy as np
x, y = [1,5,2,1], [4,6,2,3]
c = []
for i in range(0, len(x)):
f = -x[i]/(np.cos(y[i]))
c.append(f)
print(c)
Hope ... there is no specific reason ... to handle as a list.
import numpy as np
x, y = [1,5,2,1],[4,6,2,3]
c = []
for k in range (len(x)):
c = -x[k]/(np.cos(y[k]))
print(c)
Result:
1.5298856564663974
-5.207409632975539
4.805995923444762
1.0101086659079939
The error tells you the problem: TypeError: bad operand type for unary -: 'list'
So you could just negate elsewhere (where you have a NumPy array):
c = -x/np.cos(y) # Error
c = x/-np.cos(y) # [ 1.52988566 -5.20740963 4.80599592 1.01010867]
c = -(x/np.cos(y)) # [ 1.52988566 -5.20740963 4.80599592 1.01010867]
listlike a numpy-array? (if so, why avoid numpy?) Or do you want to learn how to use numpy arrays?