lets say I have a string like this:
"ID: 123 Name: Michael , ID: 124 Name: John"
I want to extract all of the ID's like a list which is the word between "ID:" and "Name:"
My desired output:
output = ['123', '124']
How can I do this most efficiently? Thank you very much=)
You can use re.findall here. You can extract Number between 'ID: number Name:.
s=" ID: 123 Name: Michael , ID: 124 Name: John "
re.findall(r'ID: (\d+) Name',s)
# ['123', '124']
Regex pattern explanation r'ID: (\d+) Name' You can read about regex Syntax
\d+ is used to capture numbers() is used to capture the pattern enclosed between them.re.findall Return a list of all non-overlapping matches in the string. If one or more capturing groups are present in the pattern, return
a list of groups; this will be a list of tuples if the pattern
has more than one group.I would suggest using a dictionary instead of storing details in a string.
details={'123':'Micheal','124':'John'}
Since every ID would be unique you can use it a key and Name as value corresponding to the key.
Try this:
[ i for i in " ID: 123 Name: Michael , ID: 124 Name: John ".split() if i.isnumeric()]
gives the output:
['123', '124']
