How to convert or typecast to binaryInteger from string?

Question

"11001001101000000100010101"

"00111000000011010000101011"

AND

= 00001000000000000000000001

Binary representation:

"11001001101000000100010101" = > 0b11001001101000000100010101

"00111000000011010000101011" = > 0b00111000000011010000101011

Two strings but value looks like binary and I want to Bitwise And Operator of two binary.

How to convert string to binary?

So you want to bitwise AND two binary strings? Do you want the result to be an Int or a String? — Sweeper
– Sweeper, Commented May 24, 2020 at 9:18
Then the res variable in Joakim Danielson's solution is what you need. — Sweeper
– Sweeper, Commented May 24, 2020 at 10:08

Joakim Danielson · Accepted Answer · 2020-05-24 11:31:14Z

1

Both UInt and String has init methods where you can give the radix (base ) of the number

let s1 = "11001001101000000100010101"
let s2 = "00111000000011010000101011"

if let binary1 = UInt(s1, radix: 2), let binary2 = UInt(s2, radix: 2) {
    let res = binary1 & binary2
    print(String(res, radix: 2))
}

output

1000000000000000000001

edited May 24, 2020 at 11:31

answered May 24, 2020 at 9:19

Joakim Danielson

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