Python compare part of string to list

Question

I have multiple strings that looks like this:

“BPBA-SG790-NGTP-W-AU-BUN-3Y”

I want to compare the string to my list and if part of the string is in the list, I want to get only the part that is found on the list as a new variable.

This is my code:

    mylist = ["770", "790", "1470", "1490"]
    sq = “BPBA-SG790-NGTP-W-AU-BUN-3Y”

    matching = [s for s in mylist if any(xs in s for xs in sq)]
    print(matching)

>>> ['770', '790', '1470', '1490']

For example this is what I want to get:

    mylist = ["770", "790", "1470", "1490"]
    sq = “BPBA-SG790-NGTP-W-AU-BUN-3Y”

    matching = [s for s in mylist if any(xs in s for xs in sq)]
    print(matching)

>>> 790

Any idea how to do this?

Red · Accepted Answer · 2020-06-01 17:40:08Z

3

Like this, you can use a list comprehension:

mylist = ["770", "790", "1470", "1490"]
sq = "BPBA-SG790-NGTP-W-AU-BUN-3Y"

matching = [m for m in mylist if m in sq]

print(matching)

Output:

['790']

answered Jun 1, 2020 at 17:40

Red

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Comments

Harka · Accepted Answer · 2020-06-01 17:43:04Z

2

You can use the in keyword from python:

mylist = ["770", "790", "1470", "1490"]
sq = "BPBA-SG790-NGTP-W-AU-BUN-3Y"
for i in mylist:
    if i in sq:
        print(i)

The code iterates through the list and prints the list element if it is in the string

answered Jun 1, 2020 at 17:43

Harka

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1 Comment

Benn Over a year ago

That was exactly what I wanted. Thank you

Eeshaan · Accepted Answer · 2020-06-01 17:43:49Z

1

Not sure I get your question, but the following should do the trick

[x for x in mylist if x in sq]

It return you with a list of those elements of the list that appears in the string

answered Jun 1, 2020 at 17:43

Eeshaan

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Comments

bro · Accepted Answer · 2020-06-01 17:46:26Z

1

try

mylist = ["770", "790", "1470", "1490"]
sq = "BPBA-SG790-NGTP-W-AU-BUN-3Y"

b = [x for x in mylist if sq.find(x) != -1]
print b

answered Jun 1, 2020 at 17:46

bro

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1 Comment

ysf Over a year ago

While this code may resolve the OP's issue, it is best to include an explanation as to how your code addresses the OP's issue. In this way, future visitors can learn from your post, and apply it to their own code. SO is not a coding service, but a resource for knowledge. Also, high quality, complete answers are more likely to be upvoted. These features, along with the requirement that all posts are self-contained, are some of the strengths of SO as a platform, that differentiates it from forums. You can edit to add additional info &/or to supplement your explanations with source documentation.

chash · Accepted Answer · 2020-06-01 17:57:50Z

0

[s for s in mylist if s in sq]

For those who dislike brevity:

This is a list comprehension. It evaluates to a list of strings s in mylist that satisfy the predicate s in sq (i.e., s is a substring of sq).

edited Jun 1, 2020 at 17:57

answered Jun 1, 2020 at 17:40

chash

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1 Comment

azro Over a year ago

Code-only answer values nothing

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