I have such an array:
const char arg_arr[][100] = {
"a",
"b",
"c",
"d",
};
and then I have such a method ParseCmdLine(const char *argv[]);
So, in order to pass my arg_arr I need to get pointer to it.
I try to invoke this method such way ParseCmdLine(*arg_arr) or like this ParseCmdLine(&arg_arr), but it doesn't work.
Question is - how to pass this arr as a pointer?
Change:
const char arg_arr[][100] = {
...
};
To:
const char *arg_arr[] = {
...
};
ParseCmdLine must have a way to tell how many elements are present in the array. Either pass this count as an extra argument (argc) or add a trailing NULL pointer after the last string, or both as is done for the arguments of the main() function.arg_arr is a constant array of arrays of char, which is a different type from what ParseCmdLine expects: a pointer to an array of pointers to constant char arrays.
You should define arg_arr this way:
const char *arg_arr[] = {
"a",
"b",
"c",
"d",
NULL
};
and pass it directly as ParseCmdLine(arg_arr).
Note that ParseCmdLine must have a way to tell how many elements are present in the array. Either pass this count as an extra argument (argc) or add a trailing NULL pointer after the last string as shown above, or both as is done for the arguments of the main() function.
How to get pointer on array?
Available options regarding what you have provided ( without changing your code ):
Numerically:
Alphabetically:
Here's a guide that I think might help.
The name of the array is essentially the address of its first element.
const char arg_arr[][100]andconst char *argv[]are incompatible. You can't convert the former to the latter; you need to rewrite the former.const char arg_arr[][100]andconst char *argv[]differ.char [][100]is an array of arrays of 100 chars.const char *argv[]is an array of pointers to const char.void ParseCmdLine(const char (*argv)[100]) {}