How to set a timeout for recvfrom in socket Python [duplicate]

Question

I have a neat little program here that just connects to servers. It is a UDP client. It is supposed to send a message to the server and wait for the response.

import socket

host = socket.gethostname() # Change to the ip address 
port  = 4000

s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
message = input('Send_To_Server: ')

while message != 'endhost':
     s.sendto(message.encode('utf-8'), (host, port))
     data, addr = s.recvfrom(1024)
     data = data.decode('utf-8')
     print("Received from server: " + data)
     message = input('Send_To_Server: ')
s.close()

The only problem is that if the server is not up, it just sits there. Is there any way to set a timeout so after so many seconds it goes over the command?

Does this answer your question? How to set timeout on python's socket recv method?, python udp client time out machinsm, Handling a timeout error in python sockets — Steffen Ullrich
– Steffen Ullrich, Commented Jul 23, 2020 at 4:25

Roshin Raphel · Accepted Answer · 2020-07-23 08:28:57Z

0

Use the settimeout function :

import socket

host = socket.gethostname() # Change to the ip address 
port  = 4000

s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
s.settimeout(10)
message = input('Send_To_Server: ')

while message != 'endhost':
     s.sendto(message.encode('utf-8'), (host, port))
     data, addr = s.recvfrom(1024)
     data = data.decode('utf-8')
     print("Received from server: " + data)
     message = input('Send_To_Server: ')
s.close()

This will set a 10s timeout.

answered Jul 23, 2020 at 8:28

Roshin Raphel

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