Regular expression - How to eliminate certain pattern in python

Question

I have some articles containing match scores like 13-9, 34-12, 22-10 which I want to extract using a regular expression to find the pattern in Python. re.compile(r'[0-9]+-[0-9]')works but how can I modify to eliminate 1999-06, 2020-01? I tried re.compile(r'[0-9]{1,2}-[0-9]')but those year values return as 99-06 which is also invalid in my case.

Try re.compile(r'(?<![0-9]{2})[0-9]{1,2}-[0-9]')

Michael Butscher
– Michael Butscher

2020-09-06 10:11:09 +00:00
Commented Sep 6, 2020 at 10:11 — Michael Butscher
– Michael Butscher, Commented Sep 6, 2020 at 10:11

Liju · Accepted Answer · 2020-09-06 10:22:46Z

1

You can match for exact number of digits required with look behind assertions, not to slice log numbers, like below

(?<!\d)\d{2}-\d{1,2}

Demo

answered Sep 6, 2020 at 10:22

Liju

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Comments

tripleee · Accepted Answer · 2020-09-06 10:13:16Z

0

You can avoid matching in the middle of a number with

r'(?<!\d)[0-9]{1,2}-[0-9]'

The negative lookbehind prohibits matching immediately after another digit.

Perhaps also add

(?!\d)

at the end to impose a similar restriction at the end of the match.

answered Sep 6, 2020 at 10:13

tripleee

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