Bash script how to extract the status code and a particular header value in two variables in one curl call

Question

Say I am making a curl request: curl -X HEAD https://example.org -i

i want HTTP Response Code and a header field 'expires' in two different variables without making http request multiple times in my shell script.

Something like this i am currently doing,

url = " -X HEAD https://example.org -i "

httpCode = `eval curl --write-out '%{http_code} ${url}`

expiresHeader = `eval curl ${url} | grep expires`

I want to make only one http request and still be able to get the two fields.

MarcoLucidi · Accepted Answer · 2020-09-21 17:59:37Z

1

you can keep the whole response head (status line and headers) in a variable and then "select" only the things you want. for example:

#!/bin/bash

url="https://example.org"

resp=`curl -s --head -i "$url"`
httpCode=`echo "$resp" | head -n 1 | cut -d ' ' -f 2`
expiresHeader=`echo "$resp" | grep "expires"`

echo "$httpCode"
echo "$expiresHeader"

$ bash script
200
expires: Mon, 28 Sep 2020 17:48:41 GMT
$

answered Sep 21, 2020 at 17:59

MarcoLucidi

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2 Comments

Jetinder Rathore Over a year ago

It works for me. I was missing 'echo' before running grep on the variable holding the response. Thanks.

MarcoLucidi Over a year ago

@JetinderRathore glad I helped you! if it fixed your problem, please mark it as the accepted answer :)

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