Store a value in an array if this doesn't exist in another array

Question

Hello i'm a beginner in nodejs and i just wanted to know how can i compare 2 array and store the difference into an other array.

i've done this to start :

const array1 = [1,2,3,4,5,6,7,8,9,0];
const array2 = [5,2,8,9];
const array3 = []; //wanted [1,3,4,6,7,0]
var i=0
array2.forEach(function(element){
  const found = array1.find(element => element !== array2[i])
    array3.push(found)
  i++
})
  console.log(array3)

Thanks a lot !

hgb123 · Accepted Answer · 2020-10-01 14:24:27Z

1

You could use filter and includes

const array1 = [1, 2, 3, 4, 5, 6, 7, 8, 9, 0]
const array2 = [5, 2, 8, 9]
const array3 = array1.filter((element) => !array2.includes(element))
console.log(array3)

answered Oct 1, 2020 at 14:24

hgb123

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Derek Wang · Accepted Answer · 2020-10-01 14:24:41Z

1

You can implement that using Array.filter & Array.includes function.

const array1 = [1,2,3,4,5,6,7,8,9,0];
const array2 = [5,2,8,9];

const result = array1.filter(item => !array2.includes(item));
console.log(result);

answered Oct 1, 2020 at 14:24

Derek Wang

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