reading multiple lines as input in scala

Question

I have a number of lines as input and want to read and print the exact same thing. The problem is I don't know how! (readLine) The input comes from a user typing in terminal.

the first integer is the number of lines in total!

input:

4
word
localization
internationalization

output:

word
localization
internationalization

the input comes from a user typing into a terminal. Beacuse readLine gets the input — Pocoya
– Pocoya, Commented Nov 1, 2020 at 8:50
readLine does read a line from stdin. What didn't work about it? — Thilo
– Thilo, Commented Nov 1, 2020 at 8:57
I want the program to read multiple lines simultaneously! readLine reads one line only — Pocoya
– Pocoya, Commented Nov 1, 2020 at 9:00
2 options: call readLine several times, or write your own utility based on InputStream — Mateusz Kubuszok
– Mateusz Kubuszok, Commented Nov 1, 2020 at 11:27

Volty De Qua · Accepted Answer · 2023-11-22 14:08:01Z

2

Something like

// default condition: string is not empty, not inclusive! 
class TermLines (cond: (String => Boolean) = _ != "") extends Iterator[String] { 
  var s = readLine; 
  def hasNext = cond(s); 
  def next = { var r = s; s = readLine; r } 
}

Then call it like

println((new TermLines).toVector.mkString("\n")) // till empty

or

println(new TermLines(_ != ".").toVector.mkString("\n")) // till last is dot

edited Nov 22, 2023 at 14:08

answered Nov 1, 2020 at 22:01

Volty De Qua

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1 Comment

hartmut27 Over a year ago

this is beautiful

Pocoya · Accepted Answer · 2020-11-03 11:45:37Z

-1

Solved!

import scala.io.StdIn

object Solution extends App
{
    val numOfLines = StdIn.readInt()
    def words: Seq[String] = for (_ <- 1 to numOfLines) yield StdIn.readLine()
    def sort = words.map
    {
        case word => word
    }
    sort.foreach(println)
}

answered Nov 3, 2020 at 11:45

Pocoya

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3 Comments

jwvh Over a year ago

The .map() call doesn't do anything so sort is exactly the same as words.

Pocoya Over a year ago

That's not the whole code. I cut the code. case word if word.length > 10 => (s"${word.head}${(word.length - 2).toString}${word.last}") case word => word. But you are RIGHT!

jwvh Over a year ago

Two sets of parens () are unneeded and the .toString is unneeded. The use of readInt() is dangerous. Glad it works for you but it's not a very good solution for the actual question as posted.

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