Looked around but couldn't find an answer to this.
Is there a more declarative way of doing this with ramda?
R.reduce((acc, val) => {
acc[val.name] = val.value
return acc
}, {}, fields)
Basically, I am converting an array that looks like this:
[
{ name: "firstName", value: "John" },
{ name: "lastName", value: "Doe" }
]
Into a single object that looks like this:
{ firstName: "John", lastName: "Doe" }
Map the the array into an array of [name, value] pairs, and then convert it to an object using R.fromPairs:
const { pipe, fromPairs, map, props } = R
const fn = pipe(map(props(['name', 'value'])), fromPairs)
const arr = [{ name: "firstName", value: "John" }, {name: "lastName", value: "Doe" }]
const result = fn(arr)
console.log(result)<script src="https://cdnjs.cloudflare.com/ajax/libs/ramda/0.27.1/ramda.min.js" integrity="sha512-rZHvUXcc1zWKsxm7rJ8lVQuIr1oOmm7cShlvpV0gWf0RvbcJN6x96al/Rp2L2BI4a4ZkT2/YfVe/8YvB2UHzQw==" crossorigin="anonymous"></script>With vanilla JS you can create the array of pairs (entries) by mapping the array, using destructuring, and then converting to object using Object.fromEntries():
const fn = arr => Object.fromEntries(arr.map(({ name, value }) => [name, value]))
const arr = [{ name: "firstName", value: "John" }, {name: "lastName", value: "Doe" }]
const result = fn(arr)
console.log(result)
const convert = (xs) => Object .fromEntries (xs .map (({name, value}) => [name, value]))