Java if a function did not get a parameter [duplicate]

Question

I tried to do something like C++:

public void function(int x = 10) { // If user did not give an parameter, parameter= 10
    }

How can I set the parameter in case he did not get?

Java doesn't support that. You should use method overloading — Alfie
– Alfie, Commented Dec 17, 2020 at 20:50

Idle_Mind · Accepted Answer · 2020-12-17 20:51:46Z

1

You'd overload it with a method that doesn't receive a parameter, then call it with the one that you want:

public void function() { function(10); }

Your original function would then just be:

public void function(int x) { // ... body ... }

answered Dec 17, 2020 at 20:51

Idle_Mind

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Comments

Arvind Kumar Avinash · Accepted Answer · 2020-12-17 21:14:57Z

1

In Java, you can achieve it using method overloading

public void function(int x) {

}

public void function() { 
    int x = 10;// If user did not give an argument, argument = 10
    function(x);
}

answered Dec 17, 2020 at 20:51

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