Scala - Load XML from file and override text values

Question

I have an XML file with many tags that carry the same info, but are required by a service I'm trying to use.

<request>
    <first>{firstName}</first>
    <first_1>{firstName}</first_1>
    <first_2>{firstName</first_2>
</request>

In order to save time, I just want to be able to load the XML file and override all values in curly braces with the matching variable name such that:

val firstName = Bob
val myXML = XML.loadFile("path_to_file")
// TODO: myXML.override("firstName", firstName)

Would yield the XML:

<request>
    <first>Bob</first>
    <first_1>Bob</first_1>
    <first_2>Bob</first_2>
</request>

Any thoughts on how to do this?

ELinda · Accepted Answer · 2021-01-23 23:33:44Z

Here is an example assuming that the variables can be stored in a standard Map.

For demonstration purposes, I added a "lastName" so there will be multiple variables.

Note that you can open and read the file into a variable such as xml, with Source.fromFile(filename).getLines.mkString or something equivalent.

Docs for Map include the foldLeft method description, but in general, it can be used to repeatedly apply a function to an initial value (xml in this case), given a collection (vars in this case) which provides parameters to this function.

val vars = Map("firstName" -> "Sally", "lastName" -> "Dunn")
val xml = """<request>
    <first>{firstName}</first>
    <first_1>{firstName}</first_1>
    <last_2>{lastName}</last_2>
</request>"""

// entry is a Map entry (or Tuple)
vars.foldLeft(xml)((res, entry) => res.replace("{" + entry._1 + "}", entry._2))

Result:

<request>
    <first>Sally</first>
    <first_1>Sally</first_1>
    <last_2>Dunn</last_2>
</request>

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