I have list of lists of strings like this:
[['today'], ['is'], ['rainy'], ['day']]
I want to print each word vertically in python. I want to output something like this
t i r d
o s a a
d i y
a n
y y
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1You need to provide more detail. Ideally you want to show the code of your attempt implementing the algorithm, where and why you think it fails, etc.0xTomato– 0xTomato2021-02-10 08:30:50 +00:00Commented Feb 10, 2021 at 8:30
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Is the list over each string intentional?. you have a list of list, where each list contains a stringRishabh Kumar– Rishabh Kumar2021-02-10 08:36:59 +00:00Commented Feb 10, 2021 at 8:36
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yes I have a list of lists of strings contain a string, but it can be converted back to a normal list of string @RishabhKumarthavha tsiwana– thavha tsiwana2021-02-10 09:02:46 +00:00Commented Feb 10, 2021 at 9:02
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3 Answers
You could try itertools.zip_longest
from itertools import zip_longest
lst = [['today'], ['is'], ['rainy'], ['day']]
print('\n'.join([' '.join([y or ' ' for y in x]) for x in zip_longest(*[i[0] for i in lst])]))
Output:
t i r d
o s a a
d i y
a n
y y
1 Comment
Jasmijn
In this case I'd use
y or ' ' instead of ' ' if y is None else yYou can do this will a loop.
l = [['today'], ['is'], ['rainy'], ['day']]
max_len = len(max(l, key=lambda x: len(x[0]))[0])
out = ''
for idx in range(max_len):
for item in l:
small_item = item[0]
if len(small_item) > idx:
out += small_item[idx]
out += "\t"
else:
out += " \t"
out += "\n"
print(out)
t i r d
o s a a
d i y
a n
y y
Idea behind this is simple. You have to find the length of longest string you have. Then basically you want to pick up each item from each string if that element is valid, else add a empty space. Add tabs and newlines to format as you want.
Comments
lst = [['today'], ['is'], ['rainy'], ['day']]
max_len = len(max(lst, key=lambda x: len(x[0]))[0])
for i in range(max_len):
for word in lst:
try:
print(word[0][i], end=' ')
except IndexError:
print(' ', end=' ')
print()
Output:
t i r d
o s a a
d i y
a n
y y
