Converting empty string to nil via split()

Question

I've got a string that I'm splitting, as follows:

foo, bar, baz, etc = str.split(',')

If, for example, str is equal to "one,two,,four", then baz ends up equalling "" (an empty string). Is there any easy way to loop through these for parameters to convert them to nil if they're an empty string? Or am I stuck doing the following?

foo = nil if foo.blank?
bar = nil if bar.blank?
baz = nil if baz.blank?
etc = nil if etc.blank?

why do you need it to be nil?

Jim Deville
– Jim Deville

2011-07-10 06:48:53 +00:00
Commented Jul 10, 2011 at 6:48 — Jim Deville
– Jim Deville, Commented Jul 10, 2011 at 6:48
Because nil and empty string are two different values.

Matt Huggins
– Matt Huggins

2011-07-10 19:09:00 +00:00
Commented Jul 10, 2011 at 19:09 — Matt Huggins
– Matt Huggins, Commented Jul 10, 2011 at 19:09

gunn · Accepted Answer · 2011-07-10 07:57:55Z

6

If you're doing this in rails, you can use the Object#presence method:

foo, bar, baz, etc = str.split(',').map(&:presence)

answered Jul 10, 2011 at 7:57

gunn

9,2152 gold badges26 silver badges24 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

antonversal · Accepted Answer · 2011-07-10 07:01:05Z

4

I can suggest you this solution:

foo, bar, baz, etc = str.split(',').map{|ss| ss.blank? ? nil : ss}

answered Jul 10, 2011 at 7:01

antonversal

1,2399 silver badges10 bronze badges

Collectives™ on Stack Overflow

Converting empty string to nil via split()

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related