Finding the right Regular Expressions in JavaScript

Question

Having hard time finding the correct regex in JavaScript.

this is the test string

[tr1,1,70,18][jl2]39th St [nl1]Adams Blvd [tr71,1,39,18][jl3]$0.70[nl1]$0.80[tr1,19,110,8][jl3]HOV2+ W/FLEX $0

and I'd like to find an expression that matches all of the 3 string below:

[tr1,1,70,18][jl2]39th St [nl1]Adams Blvd 

[tr71,1,39,18][jl3]$0.70[nl1]$0.80

[tr1,19,110,8][jl3]HOV2+ W/FLEX $0

I managed to get close with this regex which matches the [tr portions but need the rest of the text as well.

\[tr\d+,\d+,\d+,\d+\]

regex tester here.

Hao Wu · Accepted Answer · 2021-03-16 00:39:47Z

2

If there's nothing starts with [tr other than the beginning of the group, you may try this regex:

\[tr(?:(?!\[tr).)*

\[tr starting with [tr
(?:(?!\[tr).)* matching every character after it unless there's an another [tr ahead

const text = '[tr1,1,70,18][jl2]39th St [nl1]Adams Blvd [tr71,1,39,18][jl3]$0.70[nl1]$0.80[tr1,19,110,8][jl3]HOV2+ W/FLEX $0';

const regex = /\[tr(?:(?!\[tr).)*/g;

const result = text.match(regex);

console.log(result);

Or you can try this one for safer choice:

\[tr\d+,\d+,\d+,\d+\](?:(?!\[tr\d+,\d+,\d+,\d+\]).)*

answered Mar 16, 2021 at 0:39

Hao Wu

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The fourth bird · Accepted Answer · 2021-03-16 08:00:55Z

Another way could be matching the first [tr part with 1 or more comma separated digits, followed by repeatedly matching parts between square brackets that do not start with tr

\[tr\d+(?:,\d+)+](?:\[(?!tr)[^][]+][^][]*)+

The pattern matches

\[tr Match [tr
\d+(?:,\d+)+ Match 1+ digits and repeat 1+ times a comma and 1+ digits
] Match a ] char
(?: Non capture group
- \[(?!tr) Match [ and assert that it is not directly followed ty tr
- [^][]+] Match from [ till ]
- [^][]* Match 0+ times any char except [ and ]
)+ Close non capture group and repeat 1+ times

Regex demo

const s = '[tr1,1,70,18][jl2]39th St [nl1]Adams Blvd [tr71,1,39,18][jl3]$0.70[nl1]$0.80[tr1,19,110,8][jl3]HOV2+ W/FLEX $0';
const regex = /\[tr\d+(?:,\d+)+](?:\[(?!tr)[^\][\n]+][^\][\n]*)+/g;
console.log(s.match(regex));

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