Given a list of floats:
my_list = [0.3, 0.11, -0.9]
I want a string literal object:
my_string = "0.3, 0.11, -0.9"
Attempt:
print(', '.join(inputs))
> TypeError: sequence item 0: expected str instance, float found
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5 Answers
The compact way:
l = [0.3, 0.11, -0.9]
print (str(l)[1:-1])
Output:
0.3, 0.11, -0.9
Still, to be used with caution :). The "regular" way would be:
print (', '.join([str(x) for x in l]))
Comments
Try this:
print(' , '.join(str(x) for x in [0.3, 0.11, -0.9]))
1 Comment
ThePewCDestroyer
Updated your answer. Thanks :)
you can use join function of string like this:
first you have to convert float to str
my_string = ', '.join([str(i) for i in my_list])
2 Comments
ThePewCDestroyer
There are many syntax issues with this answer. I tried my_string =
', '.join([float(i) for i in inputs]) but got TypeError: sequence item 0: expected str instance, float found.
Amit Nanaware
you have to use str not float @ThePewCDestroyer
Arguably, the easiest way would be to do:
my_string = str(my_list)[1:-1]
This takes my_list, converts it into a string, and takes the characters from 1)leaving the first character at 0) to -1 (the end character is not taken)
1 Comment
ThePewCDestroyer
Oh, interesting. Ty :)
A more pythonic way is to use map to first convert all the float values to str, and then use the function join to concatenate into a string.
print(', '.join(map(str, my_list)))
This prints 0.3, 0.11, -0.9 when my_list = [0.3, 0.11, -0.9]
