How to return Json data in django

Question

Instead of rendering the html page, I want to return Json data from the following blocks of code but I don't know how to implement it. I don't want to use the rest_framework. When I use render the page renders but when I use JsonResponseit throws back an error.

views.py
from django.shortcuts import render
from django.http import HttpResponse, JsonResponse
from django.core.mail import send_mail 

def contact_us(request):
    if request.method == "POST":
        name = request.POST.get("name")
        email = request.POST.get("email")
        title = request.POST.get("title")
        message = request.POST.get("message")

        data = {
            "name": name,
            "email": email,
            "title": title,
            "message": message
        }
        message =  '''    
        New message: {}

        From: {}
        '''.format(data["message"], data['email'])
        send_mail(data["title"], message, '', ['[email protected]'])
  
    return JsonResponse(request, 'contact_us/contact_us.html', safe=False)

contact.html

<form action="" method="POST" class="contact_us">
    {% csrf_token %}
    <div>
        <div>Name</div>
        <input type="text" name="name">
    </div>
    <div>
        <div>Email</div>
        <input type="text" name="email">
    </div>
    <div>
        <div>Title</div>
        <input type="text" name="title">
    </div>
    <div>
        <div>Message</div>
        <textarea name="message" cols="30" rows='10'></textarea>
    </div>
    <div>
        <input type="submit", value="submit">
    </div>
</form>

You can't pass template in JsonResponse if you want to pass some code of HTML you can do something like this mytags = <h1>Hello</h1> and than you have to pass it like this in your JsonResponse return JsonResponse({'mymessage':mytags}) — Ankit Tiwari
– Ankit Tiwari, Commented May 31, 2021 at 15:59
Thanks @Ankit Tiwari for the explanation. In this case, the form to fill so as to send the email is in the template. How do I work arround this? Am I supposed to to copy the code for the form in the template and paste it in views.py in order for JsonResponse to work? If yes, is it a good practice? Sorry for asking many questions, I want to know how to work arround situations like this without using rest framework. I want to use a react application to fetch the Json data that will be returned. — C-Bizz
– C-Bizz, Commented May 31, 2021 at 16:15
you can do something like this in your view def send_mail(request): get_all_data_from_frontend and than send email to user after email is send to user you have to return success message as JsonResponse — Ankit Tiwari
– Ankit Tiwari, Commented May 31, 2021 at 16:19

Ankit Tiwari · Accepted Answer · 2021-05-31 16:44:36Z

1

If you are using React than you have to get data from frontend you don't need to send a template you have to create a contact page in React which contain your contact form

than you have to access all data in your view

def send_mail(request):
    if request.method == "POST":
            name = request.POST.get("name")
            email = request.POST.get("email")
            title = request.POST.get("title")
            message = request.POST.get("message")
    
            data = {
                "name": name,
                "email": email,
                "title": title,
                "message": message
            }
           current_site = get_current_site(request)
           mail_subject = 'My Subject.'
           message = get_template('contact_us/contact_us.html').render(data)
           to_email = request.POST.get('email')
           email = EmailMessage(
            mail_subject, message, to=[to_email]
            )
           email.content_subtype = "html"
           email.send()
     return JsonResponse({"Success":'Check your email.'})

you have to import this two things from django.template.loader import get_template from django.core.mail import EmailMessage

**NOTE : ** use try: except: if you want except the exceptions and use email.send(fail_silently=False) to avoid email error such as failed to send mail etc.

check official doc. for more information https://docs.djangoproject.com/en/3.2/topics/email/#emailmessage-objects

answered May 31, 2021 at 16:44

Ankit Tiwari

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3 Comments

C-Bizz Over a year ago

Thank so much @ Ankit Tiwari. When I test the code on Postman using post request I get an error: current_site = get_current_site(request) NameError: name 'get_current_site' is not defined

Ankit Tiwari Over a year ago

Hello @C-Bizz you don't need to add your current site in email the code i provided you it was used in my activate account logic i passes my current domain with token and user id but in your case you don;t need this so you can remove it

Ankit Tiwari Over a year ago

if you still want to use it for any purpose you can import it from django.contrib.sites.shortcuts import get_current_site than it will work

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