I have a script that is supposed to compare my argument number with two other numbers. If its between them it should return true, if not false
#!/usr/bin/python3
import sys
obj1 = int(sys.argv[1])
obj2 = (1900, 2100)
def range_check(obj1, obj2):
if obj1 in range(obj2):
return True
else:
return False
print(range_check(obj1, obj2))
I keep on getting "tuple integer error". Please help!
When used the way you're trying to use it, the range() function wants two arguments: start and stop, not a single tuple with the two values. There are many ways to give it two values:
def range_check(obj1, obj2):
range_start, range_stop = obj2
return obj1 in range(range_start, range_stop)
def range_check(obj1, obj2):
return obj1 in range(obj2[0], obj2[1])
range() using *:def range_check(obj1, obj2):
return obj1 in range(*obj2)
Also note:
if a == b:
return True
else
return False
is identical to
return a == b
because a == b is already True or False.
The issue you have is that the tuple needs to be unpacked. You can do this with the * operator like so:
import sys
obj1 = int(sys.argv[1])
obj2 = (1900, 2100)
def range_check(integer_value, valid_range):
return integer_value in range(*valid_range)
print(range_check(obj1, obj2))
As noted in another answer, you can omit the broken-out if statement. Also, it is best practice to use arguments that are not variables in the outer scope. This way you don't have any strange behavior with collisions shadowing one another unexpectedly.
