can someone tell me what is wrong with my code?!!
def make_list(number):
names =[]
for item in range(0,number):
names.append(input("Enter your name"))
print(names)
number = int(input("How many names need to be entered?"))
names = make_list(number)
for name in names:
if name[0] == "A":
print("Name", name)
In make_list, you're printing names, then implicitly returning None. Change the print to a return:
def make_list(number):
names =[]
for item in range(0,number):
names.append(input("Enter your name with a capital letter."))
return names
This way the caller will assign the list to names rather than None.
Rather than printing the name in the function, the fix is to return the names array.
def make_list(number):
names =[]
for item in range(0,number):
names.append(input("Enter your name with a capital letter. "))
return (names)
number = int(input("How many names need to be entered? "))
names = make_list(number)
for name in names:
if name[0] == "A":
print("Name", name, "starts with A")
Sample Output:
How many names need to be entered? 2
Enter your name with a capital letter. Andrew
Enter your name with a capital letter. Abby
Name Andrew starts with A
Name Abby starts with A
you need to return the value from the function make_list to names in the main code
def make_list(number):
names =[]
for item in range(0,number):
names.append(input("Enter your name with a capital letter."))
print(names)
return names
number = int(input("How many names need to be entered?"))
names = make_list(number)
for name in names:
if name[0] == "A":
print("Name", name, "starts with A")
def make_list(number):
names =[]
for item in range(0,number):
names.append(input("Enter your name with a capital letter. "))
return (names)
number = int(input("How many names need to be entered? "))
names = make_list(number)
for name in names:
print(f"Name {name} starts with {name[0]}")
In your original code, number=int(input("blah")) ... was inside the function make_list() so make_list() never got called. Additionally, you need to return names at the end of make_list(), otherwise it implicitly returns None, the return value of print().
