How can I get the index of any array having 'AAPL' in the following example code? The following code returned true or false. Instead of true or false, how can I get 0 and 2? Thanks for any help!
function test() {
var tickers = [], isAAPL = [];
tickers[0] = 'AAPL';
tickers[1] = 'GOOG';
tickers[2] = 'AAPL';
tickers[3] = 'MSFT';
// how to find the index of the array containing 'AAPL'? The output should be 0 and 2.
isAAPL = tickers.map(x => (x == 'AAPL'));
console.log(isAAPL);
}
function test() {
let tickers = ['AAPL', 'GOOG', 'AAPL', 'MSFT'];
let found = [];
let start = '';
var idx = '';
do {
idx = tickers.indexOf('AAPL', start);
if (~idx) {
found.push(idx);
start = idx + 1;
}
} while (~idx)
console.log(found.join(','));
}
Execution log
2:25:24 PM Notice Execution started
2:25:25 PM Info 0,2
2:25:25 PM Notice Execution completed
This works too:
function test1() {
var tickers = [], isAAPL = [];
tickers[0] = 'AAPL';
tickers[1] = 'GOOG';
tickers[2] = 'AAPL';
tickers[3] = 'MSFT';
// how to find the index of the array containing 'AAPL'? The output should be 0 and 2.
isAAPL = tickers.map((x,i) => {if(x == 'AAPL')return i;}).filter(e => !isNaN(e) );
console.log(isAAPL.join(','));
}
Here is another approach - a slight variation on the first approach in cooper's answer:
var tickers = ['AAPL', 'GOOG', 'AAPL', 'MSFT'];
var symbol = 'AAPL';
var idx = tickers.indexOf(symbol);
var isAAPL = [];
while (idx != -1) {
isAAPL.push(idx);
idx = tickers.indexOf(symbol, idx + 1);
}
console.log(isAAPL);This uses indexOf() in a loop to repeatedly find the "next" occurrence.
Each time it starts at the position following the last position where the string was found.
