Renaming multiple files using shell script

Question

I have downloaded multiple files from different s3 buckets to a single folder on a linux vm. I want to rename only the *.gz files in the directory, preferably sequentially, using a script to something like FILE001_$(date '+%Y%m%d').csv.gz,FILE002_$(date '+%Y%m%d').csv.gz etc, before moving them to client's sftp server(existing process).

I tried using find . -name "*.csv.gz" -exec mv {} FILE%03d_$(date '+%Y%m%d').csv.gz from another post but get missing argument to -exec error. Any examples using rename or mv for the above task please?

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– 0stone0, Commented Oct 11, 2021 at 10:25

ceving · Accepted Answer · 2021-10-12 08:00:36Z

2

Try something like this:

#! /bin/bash
declare -i i=0
for f in *.csv.gz; do
  : $((i++))
  mv "$f" "$(printf "FILE%03d_%s.csv.gz" $i "$(date +%Y%m%d)")"
done

You can pass the names of the files into the script. In that case you have to use dirname to get the name of the directory of each file.

#! /bin/bash
declare -i i=0
for f in "$@"; do
  : $((i++))
  mv "$f" "$(dirname "$f")"/"$(printf "FILE%03d_%s.csv.gz" $i "$(date +%Y%m%d)")"
done

Example:

$ mkdir {1,2,3}
$ touch {1,2,3}/{a,b,c}.csv.gz
$ ./rename.sh {1,2,3}/*.csv.gz
$ ls {1,2,3}
1:
FILE001_20211012.csv.gz  FILE002_20211012.csv.gz  FILE003_20211012.csv.gz

2:
FILE004_20211012.csv.gz  FILE005_20211012.csv.gz  FILE006_20211012.csv.gz

3:
FILE007_20211012.csv.gz  FILE008_20211012.csv.gz  FILE009_20211012.csv.gz

edited Oct 12, 2021 at 8:00

answered Oct 11, 2021 at 10:33

ceving

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3 Comments

CMR H Over a year ago

That works like charm, thanks! How would I modify the above to run from a different path to where the files are, or run this across multiple directories please?

Philippe Over a year ago

You can do ((i++)) which is simpler

codeholic24 Over a year ago

@CMR H : If you want to run for different directory simply may it as a generic function and pass the path at run time to the script which ceving as provided

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