How to execute the output of another command

Question

I have a CSV file where I would like to modify the following string:

${GDATEF(-4D,ddMMyyyy)}

To do so I am using the following script:

#!/usr/bin/env bash

echo "replacing >>D,ddMMyyyy)<<"
sed -i "s/D,ddMMyyyy)\}/ days\\\\\"\ \+\\\\\"%d\/%m\/%Y\\\\\"/g" $1


echo "replacing >>\${GDATEF(<< AND executing date + N days"
sed -i "s/\${GDATEF(/date -d \\\\\"`date` + /g" $1

echo "the final touch ;)"
sed -i "s/date -d /date -d/g" $1

This results in:

date -d\"Fri Oct 15 10:38:20 UTC 2021 + -4 days\" +\"%d/%m/%Y\"

Now I can take that result, remove some unnecessary characters and execute it manually:

sh-4.2# date -d "Fri Oct 15 09:20:53 UTC 2021 + -4 days" +"%d/%m/%Y"
11/10/2021

However, I would like to be able to perform that last step automatically, any ideas?

F1ko · Accepted Answer · 2021-10-15 11:04:19Z

1

Take the final result and use sed to remove \:

echo "date -d\"Fri Oct 15 10:38:20 UTC 2021 + -4 days\" +\"%d/%m/%Y\"" | sed 's+\\++'

This will output:

date -d"Fri Oct 15 10:38:20 UTC 2021 + -4 days" +"%d/%m/%Y"

If you execute that you will get:

11/10/2021

TL;DR

Here is the all in one solution:

eval $(echo "date -d\"Fri Oct 15 10:38:20 UTC 2021 + -4 days\" +\"%d/%m/%Y\"" | sed 's+\\++')

answered Oct 15, 2021 at 11:04

F1ko

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