How do you implement an interface in IronPython?

Question

The FAQ that comes with IronPython 2.0.1 says the following:

You can define interfaces in C#, build those into a DLL, and then implement those interfaces in Python code as well as pass the python objects that implement the interfaces to C# code.

I have googled and googled and googled, but haven't found how to do this. Can someone help?

Michael come lately · Accepted Answer · 2022-01-21 16:29:09Z

20

You can do it with the regular inheritance syntax of Python:

class SomeClass (ISomeInterface):
    def SomeMethod(self, parameter):
        pass

Just "inherit" the interface, implement its methods as you would any other class method, and enjoy!

edited Jan 21, 2022 at 16:29

Michael come lately

9,6418 gold badges70 silver badges97 bronze badges

answered Mar 30, 2009 at 4:32

Neil Williams

12.6k4 gold badges46 silver badges40 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Phil Over a year ago

To implement properties in an interface, you would use def get_SomeProperty(self): and def set_SomeProperty(self):

Collectives™ on Stack Overflow

How do you implement an interface in IronPython?

1 Answer 1

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related