Extract hex number from string python

Question

I'm trying to extract hex number from this string (type str) :

mystring = b'\r\n+CUSD: 2,"062506460642063706270639002006270644062E062F06450629002006230639062F0020062706440625062A063506270644",72\r\n\r\nOK\r\n'

I tried:

hexnumber= m = re.findall(r'[0-9a-fA-F]+' , mystring)
print(hexnumber)

Output:

['b', 'C', 'D', '1', '0637064406280020063A064A0631002006450648062C0648062F000A002D0020002D0020002D000A00300030003A0627064406420627062606450629000A0030003A0631062C06480639', '72']

The output i'm looking for is :

0637064406280020063A064A0631002006450648062C0648062F000A002D0020002D0020002D000A00300030003A0627064406420627062606450629000A0030003A0631062C06480639

What makes "b", "C", "2" parts invalid? Is it because they are too short? Or is it because they are not surrounded by double quotes? You need to come up with a more precise pattern that you are looking for. — Kota Mori
– Kota Mori, Commented Dec 25, 2021 at 13:14

mozway · Accepted Answer · 2021-12-25 13:20:16Z

1

You "string" is not a string with actually bytes (b'…'), so you should probably decode according to the used encoding (I assumed utf-8 here).

Then I also assumed you want to extract the string in between quotes, so I suggest using a regex with lookarounds:

import re
out = re.findall(r'(?<=")[a-fA-F\d]+(?=")', mystring.decode('utf-8'))
if out:
    print(out[0])

# 062506460642063706270639002006270644062E062F06450629002006230639062F0020062706440625062A063506270644

You can also set a minimum number of characters in your pattern (here 8 or more):

re.findall(r'[a-fA-F\d]{8,}', mystring.decode('utf-8'))

answered Dec 25, 2021 at 13:20

mozway

267k13 gold badges56 silver badges106 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Extract hex number from string python

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related