Parsing String with regular expression

Question

I am using this regular expression pattern "test(.*?\\.jpg)" in order to get the address to a JPG file out of a string . They all start with test...

Now I am facing following problem. Some of the links are ending with .JPG instead of .jpg.

How do I have to extend my regular expression to match .jpg and .JPG?

MByD · Accepted Answer · 2011-08-13 18:15:29Z

4

You can add (?i) at the beginning of the regex to make it case-insensitive:

"(?i)test(.*?\\.jpg)"

answered Aug 13, 2011 at 18:15

MByD

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tobias · Accepted Answer · 2011-08-13 19:08:20Z

2

This should work: test(.*?\\.(?:jpg|JPG))

edited Aug 13, 2011 at 19:08

tobias

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answered Aug 13, 2011 at 18:15

kjetilh

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