How to change array's variables by address in C?

I'm trying to change array's variables address by swapping the address, not the value. I have a function that swap the numbers in the array: a[0]=a[9] , a[9]=a[0], a1=a[8] , a[8]=a1, a[2]=a[7] , a[7]=a[2], ec`. If you look at the image, for example in the array arr[0] = 33, address is 00...E8. I want to swap it with the last number to be arr[0] = 10 with address of 00..0C. now I have arr[0] = 10, address 00...E8, i switched the value and not the address.

how can I implement this?

#include <stdio.h>
#include <stdlib.h>
#include<time.h>


void invert(int arr[], int size)
{
    int n;
    int temp;
    for (n = 0; n < size / 2; n++)
    {
        temp = arr[n];
        arr[n] = arr[size - 1 - n];
        arr[size - 1 - n] = temp;
    }
    printf("after invertion");
    printf("\n");
    for (n = 0; n < 10; n++)
    {
        printf(" %d ", arr[n]);
        printf(" %p\n", &arr[n]);
    }

}
void main()
{
    int arr[10];
    int i;

    srand(time(NULL));
    for (i = 0; i < 10; i++)
    {
        arr[i] = rand() % 50;
    }

    printf("before invertion");
    printf("\n");
    for (i = 0; i < 10; i++)
    {
        printf(" %d ", arr[i]);
        printf(" %p\n", &arr[i]);
    }
    printf("\n");
    invert(arr, 10);
}